Show My Homework: Relativity
a) $t2A = X_A/V = 200/(0.6*c) = 1.11*10^{-6} sec$
b) in the moving reference system the rest length are seen contracted.. Thus the intervals of time becomes bigger.
$\Delta(t_B) = t2A/\sqrt{(1-V^2/c^2)} =1.11*10^{-6}/\sqrt{(1-0.6^2)} =1.3875*10^{-6} sec$
c) $XB1 =XA1=0 m$
$XB2 = XA2/\sqrt{(1-v^2/c^2)} = 200/\sqrt{(1-0.6^2)} =160 m$
(The length in moving reference system are seen contracted.)
d) proper time is by definition
$\tau = \sqrt{(\Delta(t)^2 – \Delta(x)^2/c^2)} =$
$= \sqrt {[(1.1*10^{-6})^2 -(200)^2/c^2]} =8.7496*10^{-7} seconds$
for explanations see http://en.wikipedia.org/wiki/Proper_time#In_special_relativity)
e) the length of the ruler for a B observer is
The length in moving reference system are seen contracted.
$LB = LA/\sqrt{(1-v^2/c^2)} =200/\sqrt{(1-0.6^2)} =160 m$
f) The proper length is:
$L = c*\tau = 3*10^8*8.7496*10^{-7} =262.488 m$
$L = (c^2*\Delta(t)^2 -\Delta(x)^2) =262.488 m$
(for explanations see http://en.wikipedia.org/wiki/Proper_length#Proper_length_or_rest_length)